Question

Probleme 14;22;23 și 24 va rogg

Answer 1

14)
a=2ⁿx2³x7ⁿ+7ⁿx7x2ⁿ-3x14ⁿ
a=(2x7)ⁿx8+(2x7)ⁿx7-3x14ⁿ
a=14ⁿx8+14ⁿx7+3x14ⁿ
a=14ⁿ(8+7-3)
a=14ⁿx12⇒a se divide cu 12

22)
a)
n:12=C1 rest 5⇒n=12C1+5⇒n-5=12C1
n:18=C2 rest 5⇒n=18C2+5⇒n-5=18C2
Calculam c.m.m.m.c. al nr.12 si 18
12=2²x3
18=2x3²
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[12,18]=2²x3²=4x9=36

n-5=36
n=36+5
n=41

b)
100<n<200
n>100
n<200
n∈{101,102,103,104,....199}