Question

Probleme care se rezolva prin Metoda grafica: Daca a+b=108 si a-b=42,sa se afle a si b.

Answer 1

a+b=108

a-b=42 =>
a=b+42


a) |---|+42
b) |---| }acolada la ambele 108

108-42=66 =>
Avem doua segmente egale =>

66:2=33 (b)
33+42=75 (a)

verificare :

a+b=75+33=108 (adevărat )
a-b=75-33=42 (adevărat )

Answer 2

a + b = 108

a - b = 42 ⇒ a = b + 42

Reprezint grafic numerele

a l--------------l + 42 } suma lor = 108

b l--------------l

108 - 42 = 66 → suma celor 2 parti egale

66 : 2 = 33 → ( b)

33 + 42 = 75 ( a)