Matematică, întrebare adresată de andra2110, 9 ani în urmă

problemele 2 si 5 , va rog

Anexe:

Răspunsuri la întrebare

Răspuns de corneadiana23
1
2)2x+6y+3x+3y=8
2x+3y-3x-3y=-5

5x+9y=8
-x=-5

5x+9y=8
x=5

25+9y=8
x=5

9y=8-25
9y=17
y=17/9
x=5

5)E(x)=(x-2)(x+2)(x²+3x+2)+(x+1)(x-1)(x²+3x+2)+(x²-5)(x+1)(x+2)/(x+1)(x+2)(x²+3x+2)=(x²+2x-2x-4)(x²+3x+2)+(x²-x+x-1)(x²+3x+2)+(x³+x²-5x-5)(x+2)/(x²+2x+x+2)(x²+3x+2)=x⁴+3x³+2x²-4x²-12x-8+x⁴+3x³+2x²-x²-3x-2+x⁴+2x³+x³+2x²-5x²-10-5x-10/x⁴+3x³+2x²+2x³+6x²+4x+x³+3x²+2x+2x²+6x+4=3x⁴+9x³-4x²-20x-30/x⁴+6x³+12x²+12x+4
Răspuns de chertesiulia24
0
y=17/9
x=5

5)E(x)=(x-2)(x+2)(x²+3x+2)+(x+1)(x-1)(x²+3x+2)+(x²-5)(x+1)(x+2)/(x+1)(x+2)(x²+3x+2)=(x²+2x-2x-4)(x²+3x+2)+(x²-x+x-1)(x²+3x+2)+(x³+x²-5x-5)(x+2)/(x²+2x+x+2)(x²+3x+2)=x⁴+3x³+2x²-4x²-12x-8+x⁴+3x³+2x²-x²-3x-2+x⁴+2x³+x³+2x²-5x²-10-5x-10/x⁴+3x³+2x²+2x³+6x²+4x+x³+3x²+2x+2x²+6x+4=3x⁴+9x³-4x²-20x-30/x⁴+6x³+12x²+12x+4
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