Question

problemele 5 si 6
pe 5 va rog sa o explicați

Answer 1

5)

[tex]\it \mathcal{V} = \mathcal{A}_b\cdot h, \ \ \ h = AA' = 4 cm \\\;\\ \\\;\\ \mathcal{A}_b= \dfrac{\ell^2\sqrt3}{4} = \dfrac{AB^2\sqrt3}{4} =\dfrac{4^2\sqrt3}{4}=\dfrac{4\cdot4\sqrt3}{4}=4\sqrt3 \ cm^2 \\\;\\ \\\;\\ \mathcal{V} = 4\sqrt3\cdot 4 = 16\sqrt3 \ cm^3 [/tex]

6)

A --- 5
B --- 4
C --- 3
D --- 3

5+4+3+3 = 15