Question

Problemele 68 si 69, multumesc mult!

Answer 1

Buna!

68.
78..........x
C6H6+HONO2–>C6H5NO2+H2O
78..........63

Cm=n/Vs
x=63 grame HONO2
n=m/M
n=63/63=1mol HONO2
5=1/Vs=>Vs=1/5=0,2litri HONO2
0,2•25/100=0,05
Deci 0,2+0,05=0,25l
Adică 250 ml
Varianta A

69.
.........................x...........................3,92
C6H12O6+2[Ag(NH3)2]OH—>C6H12O7+
........................2•159.................196
2Ag+4NH3+H2O

x=6,36grame reactiv tollens

n=m/M=>n=6,36/159=0,04 moli
V=40ml=0,04litri
Molaritatea=0,04/0,04=1
Varianta D