Question

produsul obtinut la arderea a 3.36 l de H2S a fost trecut prin solutia de hidroxid de potasiu care contine 16.8 g KOH

Answer 1

n(niu)= V/Vm
n=3,36l/22,4l/mol= 0,15mol H2S

1,5mol............................1,5mol
H2S  +3/2O2----> H2O+SO2

1,5mol.....................1,5mol
SO2 + 2KOH-----> K2SO3 + H2O   K2SO3-SULFIT DE POTASIU

m= n x M
M= (2X39gK+ 32gS+ 3X16gO0/mol=158g/mol
m= 0,15molx158g/mol=......................calculeaza !!!!