Question

progresie geometrica..cum fac?... multumesc :)

Answer 1

Calculezi ratia care e q=1/2:1=1/2
Sn=b1(qⁿ-1)/q-1
b1 e la tine 1
q il stii si inlocuiesti

Answer 2

(1-1/2^5)/(1-1/2)=((2^5-1)/2^5):1/2=((2^5-1)/2^5 )*2= (2^5-1)/2^4=
=2-1/2^4=2-1/16=
1si15/16=31/16

altfel babeste clasa  a 5-a aducem la acelasi numitor

16/16+8/16+4/16+2/16+1/16=(16+8+4+2+1)/16=31/16