Question

pt. a obtine 300 ml sol. de H2SO4 5M (q=1,28 g/cm3) se amesteca X ml sol de H2SO4 20% (q=1,14) cu Y ml sol. de H2SO4  98% (q=1,84).Calculati volumele X si Y.

Answer 1

cM1=20*1,14*10/98 = 2,32 M
cM2=98*1,84*10/98 = 18,4M
14,8............5-2,32=2,68
           5
2,32............13,4 parti de 5M si 16,08 parti de 2,32 M
=>16,08 parti........300ml
1 parte...............x ml             x = 18,71ml
Vx = 18,71 * 13,4 = 250 ml
Vy = 18,71 * 2,68 = 50 ml
OBS:Am folosit regula dreptunghiului