Question

Punctele A,B si C sunt coliniare iar unghiul ABD=a,unghiul DBE=b,unghiul EBC=c.Stiind ca 3•a=2•b=6•c.

Answer 1

3a=2b=6c <=> a/91/3)+b/(1/2)+c/(1/6)=(a+b+c)/ (1/3+1/2+1/6)=

=180°/(2/6+3/6+1/6)=180°/(6/6)=180°

Daca 3a=180° => a=60°;  daca 2b=180° => b=90° => DB⊥BE.

sper ca e okk