Question

Punctele a, d, e, f rezolvare completa! Le-am facut dar nu imi da rezultatul corect.

Answer 1

$a) \\ \\ 2 \frac{1}{3} \times 3 \frac{1}{2} \times \frac{2}{3} = \frac{2 \times 3 + 1}{3} \times 3 \frac{1}{2} \times \frac{2}{3} = \frac{6 + 1}{3} \times 3 \frac{1}{2} \times \frac{2}{3} = \frac{7}{3} \times 3 \frac{1}{2} \times \frac{2}{3} = \frac{7}{3} \times \frac{3 \times 2 + 1}{2} \times \frac{2}{3} = \frac{7}{3} \times \frac{6 + 1}{2} \times \frac{2}{3} = \frac{7}{3} \times \frac{7}{2} \times \frac{2}{3} = \frac{7 \times 7 \times 2}{3 \times 2 \times 3} = \frac{98}{18} = \frac{49}{9} = 5 \frac{4}{9}$

$d) \\ \\ ( - 5 \frac{1}{6}) \times ( - 1 \frac{1}{31}) \times ( - \frac{8}{10}) = - \frac{5 \times 6 + 1}{6} \times - 1 \frac{1}{31} \times \frac{ - 8}{10} = - \frac{30 + 1}{6} \times - 1 \frac{1}{31} \times \frac{ - 8}{10} = - \frac{31}{6} \times - 1 \frac{1}{31} \times \frac{ - 8}{10} = - \frac{31}{6} \times \frac{ - (1 \times 31 + 1)}{31} \times \frac{ - 8}{10} = - \frac{31}{6} \times \frac{ - (31 + 1)}{31} \times \frac{ - 8}{10} = - \frac{31}{6} \times \frac{ - 32}{31} \times \frac{ - 8}{10} = - \frac{31 \times - 32 \times - 8}{6 \times 31 \times 10} = - \frac{7936}{1860} = - \frac{64}{15} = - 4 \frac{4}{15}$

$f) \\ \\ ( + 2 \frac{3}{5}) \times ( - 4 \frac{1}{2}) \times ( - \frac{9}{13}) = \frac{2 \times 5 + 3}{5} \times - 4 \frac{1}{2} \times \frac{ - 9}{13} = \frac{10 + 3}{5} \times - 4 \frac{1}{2} \times \frac{ - 9}{13} = \frac{13}{5} \times - 4 \frac{1}{2} \times \frac{ - 9}{13} = \frac{13}{5} \times \frac{ - (4 \times 2 + 1)}{2} \times \frac{ - 9}{13} = \frac{13}{5} \times \frac{ - (8 + 1)}{2} \times \frac{ - 9}{13} = \frac{13}{5} \times \frac{ - 9}{2} \times \frac{ - 9}{13} = \frac{13 \times - 9 \times - 9}{5 \times 2 \times 13} = \frac{1053}{130} = \frac{81}{10} = 8 \frac{1}{10}$

$e) \\ \\ ( - 4 \frac{2}{9}) \times \frac{18}{19} \times ( - 1 \frac{1}{4}) = - \frac{4 \times 9 + 2}{9} \times \frac{18}{19} \times - 1 \frac{1}{4} = - \frac{36 + 2}{9} \times \frac{18}{19} \times - 1 \frac{1}{4} = - \frac{38}{9} \times \frac{18}{19} \times - 1 \frac{1}{4} = - \frac{38}{9} \times \frac{18}{19} \times \frac{ - (1 \times 4 + 1)}{4} = - \frac{38}{9} \times \frac{18}{19} \times \frac{ - (4 + 1)}{4} = - \frac{38}{9} \times \frac{18}{19} \times \frac{ - 5}{4} = - \frac{38 \times 18 \times - 5}{9 \times 19 \times 4} = - \frac{ - 3420}{684} = - ( - \frac{3420}{684}) = - ( - 5) = 5$