Question

punctul 5 aprofundare

Answer 1

a)ac+bc=168
c=7
c(a+b)=168 <=> 7(a+b)=168 => a+b=168÷7=24
b)ac-bc=540
a-b=12
c(a-b)=540
12c=540 => c=540÷12=45
c) a+b=23
c=12
ac+bc= c(a+b)= 12×23=276
d) a-b=34
c=16
ac-bc= c(a-b)= 16×34=544
Succes!

Answer 2

a) ac+bc=531 c(a+b)=531 c=9 9(a+b)=531 a+b=531/9=59; b) ac-bc=120 c(a-b)=120 a-b=20 20c=120 c=6; c) a+b=23 c=11 ac+bc=c(a+b)=11×23=; d) a-b=78 c=24 ac-bc=c(a-b)=24×78=;