Question

Punctul a,d va rog de ele am nevoie

Answer 1

a)(15/16:15/4+27/32:27/8)·2-(-6/5+2/9·9/2):(-2/5)=
   (15/16·4/15+27/32·8/27)·2-(-6/5+1)·(-5/2)=
   (1/4+1/4)·2-(-6+5)/5·(-5/2)=
    1/2·2-(-1/5)·(-5/2)=
     1-1/2=
      1/2

d)(4/10-17/15:8/3+51/20·60/17·5/9)·5=
    (2/5-17/5·3/8+5)·5=
    (2/5-51/40+5)·5=
    (2x8-51+5x40)/40·5=
    (16-51+200)/8=
      165/8=
       20 intregi 5/8