Question

punctul A de la exercitiul 5 cu functii. 100p

Answer 1

Răspuns:

5.

a) f(x) = mx-3

A(m, 3m+1) ∈Gf ⇔ f(m) = 3m+1

⇔ m·m-3 = 3m+1

m²-3m-4 =0

m²+m-4m-4 =0

m(m+1)-4(m+1) = 0

(m+1)(m-4) = 0

⇒ $\left \{ {{m+1 = 0} \atop {m-4 = 0}} \right. <=> \left \{ {{m_{1} = -1} \atop {m_{2} = 4}} \right.$

m₁,₂ ∈ Z