Question

punctul a) va rog !!! coroana!!!

Answer 1

$\frac{4}{ x^{2} +4x } * ( \frac{4x+1}{9x} - \frac{x-6}{6x} ) = [tex] \frac{4}{x(x+4)} * ( \frac{4x+1}{3*3x} [amplifici.cu.2] - \frac{x-6}{2*3x} [amplifici.cu.3] ) = [tex] \frac{4}{x(x+4)} * ( \frac{4x+1}{18x} - \frac{x-6}{18x} ) = [tex] \frac{2}{x(x+4)} * \frac{8x+2-3x+18}{9x} = [tex] \frac{2}{x(x+4)} * \frac{5x+20}{9x} = [tex] \frac{2}{x(x+4)} * \frac{5(x+4)}{9x} = [tex] \frac{2}{x} * \frac{5}{9x} = [tex] \frac{10}{9 x^{2} }$