Question

Punctul c)
Substanta C-metan care se transforma in HCN( d in problema) in prezenta de Pt,1000 grade Celsius.
Va rog frumos!

Answer 1

Dupa racire HCN devine gaz
CH4 + NH3 + 3/2 O2 = HCN + 3 H2O
1 mol HCN.....1 mol CH4........1mol NH3.......1.5 moli O2
a............................b.......................c.......................d
a=b=c
d=1.5a
n am final = n CH4 + n NH3 + n O2 + n HCN = 1-a + 1-a + 2-1.5a + a = 4-2.5a
masa molara amestec = n ch4/n am*16+n nh3/n am*17+n o2/n am*32+n hcn/n am*27 => masa molara amestec * n am = ................
27.657 * (4-2.5a) = 1-a)*16+1-a)*17+2-1.5)*32+27a => a = 0.9 moli CH4
randamentul = nr moli practic/nr moli teroretic *100 = 0.9/1*100 = 90%