Question

Punctulb) va rog!!!!!!!

Answer 1

3x+2√3x+x-3√3x+√3=5x-12+5√3x-√36
4x-√3x+√3=5x-18+5√3x
4x-5x-√3x-5√3x= -18-√3
-x-6√3x= -18-√3 /×(-1)
x+6√3x=18+√3

Answer 2

b) ( √3 + 1 )²x - ( 3x - 1 )√3 = 5x - 12 + √3( 5x - √12 ) 
( 3 + 2√3 + 1 )x - ( 3√3x - √3 ) = 5x - 12 + √3( 5x - 2√3 )
( 4 + 2√3 )x - 3√3x + √3 = 5x - 12 + 5√3x - 6
4x + 2√3x - 3√3x + √3x = 5x - 18 + 5√3x
4x - √3x + √3 = 5x - 18 + 5√3x
4x - √3x - 5x - 5√3x = - 18 - √3
-x - 6√3x = - 18 - √3
x = ( - 18 - √3 ) / ( - 1 - 6√3 )
x = ( - 18 - √3 )( - 1 + 6√3 )/ - 107
x = ( 18 - 108√3 + √3 - 18 )/ - 107
x = - 107√3/ - 107
x = √3