Question

Pune paranteze acolo unde este cazul astfel încât egalitatile să fie adevărate. 3+3×3÷3×3=2; 3+3×3÷3×3=12; 4+4÷4+4=9; 4+4÷4+4=1; 4+4÷4+4=6 ; 5+5×5×5÷5=50; 5+5×5×5÷5=30; 5+5×5×5×5=26.

Answer 1

[(3+3)x3]:(3x3)=2
(6x3):9=2
18:9=2
2=2

3+3x3:3x3=12
3+(3x3:3)x3=12
3+(9:3)x3=12
3+3x3=12
3+9=12
12=12

4+(4:4)+4=9
4+1+4=9
9=9

(4+4):(4+4)=1
8:8=1
1=1


[(4+4):4]+4=6
(8:4)+4=6
2+4=6
6=6

[(5+5) x5]x(5:5)=50
(10x5)x1=50
50x1=50
50=50


5+(5x5) x(5:5) =30
5+25x1=30
5+25=30
30=30


5+5x5x5:5=26