Question

Pupici tuturor am nevoie de ajutor !!!

la b) și la c)


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3 ))​

Answer 1

$\it T.\ h.\ \Rightarrow\ AD^2=BD\cdot CD\ \Rightarrow BD=\dfrac{AD^2}{CD}=\dfrac{9,6^2}{7,2}=\dfrac{^{5)}92,16}{7,2}=\dfrac{460,8^{(6}}{36}=\\ \\ \\ =\dfrac{76,8^{(3}}{6}=\dfrac{25,6}{2}=12,8\ dm\\ \\ \\ BC=BD+CD=12,8+7,2=20\ dm$