Question

puteti sa ma ajutati? ​

Answer 1

a)

$f(x)=x^2+1\\A(2,a)\in G_f\Rightarrow f(2)=a\Rightarrow 2^2+1=a\Rightarrow a=5$

b)

$\displaystyle f(x)=\frac{a}{x}+1\\\displaystyle B(-3,-2)\in G_f\Rightarrow f(-3)=-2\Rightarrow\frac{a}{-3}+1=-2\Rightarrow \frac{-a}{3}=-3\Rightarrow a=9$

c)

$f(x)=1-3x\\C(2a,7)\in G_f\Rightarrow f(2a)=7\Rightarrow 1-6a=7\Rightarrow a=-1$