Question

puteti sa ma ajutati cu ex acesta?​

Answer 1

a)

a + (b + c) = (a + b) + c = a + b + c

$a + b = \frac{5}{2}$

$c = \frac{ - 1}{3}$

$a + b + c = \frac{5}{2} + \frac{ - 1}{3} = \frac{5 \times 3}{2 \times 3} + \frac{ - 1 \times 2}{2 \times 3}$

$= \frac{5 \times 3 + ( - 1) \times 2}{2 \times 3} = \frac{15 - 2}{6} = \frac{13}{6}$

b)

(a + c) + (b + d) = a + b + c + d = (a + d) + (c + b)

$a + d = - \frac{5}{3}$

$c + b = - \frac{1}{3}$

$(a + d) + (c + b) = - \frac{5}{3} + (- \frac{1}{3} ) = - \frac{5}{3} - \frac{1}{3}$

$= \frac{ - 5 - 1}{3} = \frac{ - 6}{3} = - \frac{6}{3} = - 2$