Question

Puteti sa mi faceti o rezolvare completa a primelor 2 exercitii, va rog mult.
Multumesc!

Answer 1

Rezolvarea in atasament

Answer 2

$1) \\ \\ ( \frac{2}{5 \sqrt{3} } - \frac{1}{ \sqrt{12} } + \frac{3}{ \sqrt{75} }) \times 2 \sqrt{3} = \\ \\ ( \frac{2}{5 \sqrt{3} } - \frac{1}{2 \sqrt{3}} + \frac{3}{5 \sqrt{3} }) \times 2 \sqrt{3} = \\ \\ ( \frac{2 \sqrt{3} }{5 \times 3} - \frac{ \sqrt{3} }{2 \times 3} + \frac{3 \sqrt{3} }{5 \times 3}) \times 2 \sqrt{3} = \\ \\ ( \frac{2 \sqrt{3} }{15} - \frac{ \sqrt{3} }{6} + \frac{3 \sqrt{3} }{15}) \times 2 \sqrt{3} = \\ \\ ( \frac{2 \sqrt{3} }{15} - \frac{ \sqrt{3} }{6} + \frac{ \sqrt{3} }{5}) \times 2 \sqrt{3} = \\ \\ \frac{5 \sqrt{3} }{30} \times 2 \sqrt{3} = \\ \\ \frac{ \sqrt{3} }{6} \times 2 \sqrt{3} = \\ \\ 2 \sqrt{3} \times \frac{ \sqrt{3} }{6} = \\ \\ \frac{2}{6} \sqrt{3} \sqrt{3} = \\ \\ \frac{1}{3} \sqrt{3} \sqrt{3} = \\ \\ \frac{1}{3} \sqrt{3 \times 3} = \\ \\ \frac{1}{3} \sqrt{9} = \\ \\ \frac{1}{3} \times 3 = 1 \\ \\ 2) \\ \\ \frac{x + y}{y} = \frac{7}{3} \\ \\ 1 + \frac{x}{y} = \frac{7}{3} \\ \\ \frac{x}{y} = \frac{7}{3} - 1 = \frac{4}{3}$