Question

Puteți sa Rezolvați problema din imagine??

Answer 1

Asupra corpului de masa $m_1$ actioneaza fortele astfel:

$\vec{G_1}+\vec{F_{f1}}+\vec{T}=0\implies T+\mu N_1=m_1g$

$\vec{N_1}=m_1\vec{a}\implies T=m_1g-\mu m_1a$

Asupra corpului de masa $m_2$ actioneaza fortele astfel:

$\vec{F_{f2}}+\vec{T}=m_2\vec{a}\implies T=\mu m_2g+m_2a$

Egaland cele doua relatii ale lui $T$, obtinem:

$\mu m_2g+m_2a=m_1-\mu m_1a\implies a(m_1\mu +m_2)=g(m_1-\mu m_2)$

De aici, obtinem expresia acceleratiei:

$a=g\left(\dfrac{m_1-\mu m_2}{m_2+\mu m_1}\right)=10\cdot \frac{5-4}{20+1} \dfrac{m}{s^2}=\frac{10}{21}\dfrac{m}{s^2}\approx \boxed{0,476\dfrac{m}{s^2}}$