Question

puteti va rog sa rezolvati ex atasate, sunt pentru maine va rog frumos!​

Answer 1

rezolvarea este in imaginea de mai jos

Answer 2

$\bf 107)\ \it 16x^2+8x+1=16x^2+4x+4x+1=4x(4x+1)+(4x+1)=\\ \\ =(4x+1)(4x+1)=(4x+1)^2$

Mai direct, folosim formula :

$\it 16x^2+8x+1=(4x)^2+8x+1^2=(4x+1)^2$

$\it 8x=2\cdot4x\cdot1$

$\bf 116) \it \ 3x^2-2x\sqrt3+1=(\sqrt3x)^2-2x\sqrt3+1^2=(x\sqrt3-1)^2$

$\bf 113)\it\ \ 49x^2-14x+1=(7x)^2-14x+1^2=(7x-1)^2\\ \\ 14x=2\cdot7x\cdot1$

$\bf 119) \it\ \ 5+2x\sqrt5+x^2=(\sqrt5)^2+2x\sqrt5+x^2=(\sqrt5+x)^2$