Question

Puțin ajutor la 1 și 4 ..

Answer 1

nC7H8=m/M=>nC7H8=2760/92=30kmoli toluen
C₇H₈ + Cl₂ --> C₇H₇-Cl + HCl (2)
C₇H₈ + Cl₂ --> C₇H₇-Cl + HCl (4)
C₇H₈ + 2Cl₂ -> C₇H₆=Cl₂ + 2HCl (2 si 4)
C₇H₈ -> C₇H₈
ntoluen=namestec=30kmoli
Cu/100=nutil/ntotal => 60/100=nutil/30 => nutil=18kmoli 4-clorotoluen
raport molar de 2:9 => 2x kmoli de 2-cloro si 9x kmoli 4-clorotoluen
9x==> x=2kmoli => 4kmoli de 2-clorotoluen
Ct/100=ntransformati/ntotal
=>80/100=ntransformati/30 => ntransformati=24kmoli
ntrans=namestec=>23=18+4+y => y=1kmol de 2,4diclorotoluen
nnetrans=6kmoli
22,4m³ 1kmol
C₇H₈ + Cl₂ -> C₇H₇-Cl + HCl
a=? 23kmoli
44,8m³ 1kmol
C₇H₈ + 2Cl₂ -> C₇H₆=Cl₂ + 2HCl
b=? 1kmol
a=515,2m³ si b=44,8m³
VCl₂ consumat=560m³