Question

putin ajutor , va rog

Answer 1

$a=log_34\\ \\ log_224=log_2(3*8)=log_23+log_28=log_23+3\\ \\ a=log_34~\Leftrightarrow~\frac{a}{2} =log_32 ~\Leftrightarrow~\frac{1}{log_23}= \frac{a}{2}~\Leftrightarrow~log_23=\frac{2}{a} \\ \\ Deci,~log_23+3=\frac{2}{a} +3=\frac{3a+2}{a}.\\ \\ \boxed{Raspuns~corect~a)}$