Question

Putin ajutor, va rog ?
La prima poza am nevoie de rezolvarea acelor puncte a si b incercuite cu creionul, iar la a doua poza la toate 3 .. 

Answer 1

o sa refac pozele cu recalcularea

Answer 2

b)3/√2 rationalizam=3√2/√2²=3√2/2
√9/√32=3/√32=3√32/32=3√2⁵/32=3·4√2/32=3√2/8
√49/√8=7/√8=7√8/8=7√2³=7·2√2/8=7√2/4
5/√2=5√2/2
√18=√2·3²=3√2
(3√2/2+3√2/8+7√2/4-5√2/2)·(√2+3√2)= aducem la acelasi numitor i paranteza=
(12√2+3√2+14√2-20√2)/8·4√2=
9√2/8·4√2=(9·2)/2=9

c)√1300=√(2²·5²·13)=10√13
2√52=2√(2²·13)=4√13
12√1intreg4/9=12√(13/9)=12√13/3=4√13
5√3intreg1/4=5√(13/4)=5√13/2
(10√13-4√13-4√13+5√13/2)·1/√13=
(20√13-8√13-8√13+5√13)/2·1/√13=
9√13/2·1/√13=9√13/2√13=9/2=4,5

3a)3/√2=3√2/2
(√2+3√2/2)·√2-3=
(2√2+3√2)/2·√2-3=
5√2/2·√2-3=5·2/2-3=5-3=2
b)
(√2-1)/√2=√2(√2-1)/2=(2-√2)/2
(√3-√2)/√6=√6(√3-√2)/6=(√18-√12)/6=(3√2-2√3)/6
(√4-√3)/√12=√12(2-√3)/12=2√3(2-√3)=(4√3-12)/12=4(√3-3)/12=(√3-3)/3
(√5-√4)/√20=√20(√5-√4)/20=(√100-√80)/20=(10-4√5)/20=2(5-2√5)/20=(5-2√5)/10
(√6-√5)/√30=√30(√6-√5)/30=(√180-√150)/30=(6√5-5√6)/30
(2-√2)/2+(3√2-2√3)/6+(√3-3)/3+(5-2√5)/10+(6√5-5√6)/30=
(30-15√2+15√2-10√3+10√3-30+15-6√5+6√5-5√6)/30=
(15-5√6)/30=5(3-√6)/30=(3-√3)/6
c)
(-1)³³=-1
√0,25=0,5
20/√300=20√300/300=2·10√3/30=2√3/3
√192/12=8√3/12=2√3/3
-1+2,5:0,5-2√3/3+2√3/3=
-1+25/10:5/10=-1+25/10·10/5=-1+5=4