Question

Puțin ajutor, va rog..w

Answer 1

m amestec= 400 g
%CaO=70%
%MgO=30%

m CaO= 0.7 x 400=280 g => n CaO =4.993 ~ 5 mol CaO
m MgO= 0.3 x 400=120 g

MgO + 2HCl => MgCl2 + H2O
n MgO = 120/ 40.3 = 2.97 mol
1 mol MgO .... 2 mol HCl ... 1 mol MgCl2
2.97 mol MgO ...a mol HCl ......b mol MgCl2
a= 5.96 mol HCl = 217.37 g (md)=> ms = 217.37 x 100/36.5=595.53 g sol HCl 36.5 %
b= 2.97mol MgCl2 = 282.78 g

Asadar...dupa multe calcule inutile.. :)) .. raspunsul corect : A