Question

Puțin ajutor va roggg :)))))​

Answer 1

Răspuns:

Explicație pas cu pas:

4

a) x+3=0     x=-3  nu are solutie in N

b)2x-4=0    x=2    solutie in N

c)3x+1=0    x=-1/3   nu are solutie in N

d)4x-6=0    x=3/2     nu are solutie in N

e)3x-9=0    x=3    solutie in N

f)2x=x         x=0  solutie in N

5

a)2x-3=0     x=3/2   nu are solutie in Z

b)3x+3=0   x=-1      solutie in Z

c)4x-8=0     x=2      solutie in Z

d)13x+169=0    x=-13  solutie in Z

e)√3x-3√3=0    x=3  solutie in Z

f)√2x+2√2=0   x=-2   solutie in Z