Chimie, întrebare adresată de reemjosaimi, 8 ani în urmă

Quantum numbers (n,l,m) of the fifth electron in the oxygen atom(O8) :

Răspunsuri la întrebare

Răspuns de MihaiN16
4

Answer:

n = 2; l = 1; m = -1

Explanation:

The principal quantum number (n) describes the electron shell, or energy level, of an electron. The value of n ranges from 1 to 7.

The angular quantum number (l) describes the subshell. The value of l ranges from 0 to n - 1.

The magnetic quantum number (m) describes the orbital. The value of m ranges from -l to +l.

The electron configuration of oxygen is 1s²2s²2p⁴.

The fifth electron in the oxygen atom is located in the 2px orbital of the 2p subshell of the second shell.

Second shell indicates that n = 2.

The second shell has two subshells: 2s and 2p. The 2s subshell has l = 0 and the 2p subshell has l = 1. Our electron is in the 2p subshell, so l = 1.

The 2p subshell has three orbitals: 2px (m = -1), 2py (m = 0) and 2pz (m = +1). The 5th electron is in the 2px orbital, so m = -1.

I hope this helps even a little!

-Mihai

Anexe:
Alte întrebări interesante