Question

Rad 8+Rad 27+Rad 32-rad 234-6rad 2

Answer 1

Răspuns:

$\sqrt{8} + \sqrt{27} + \sqrt{32} - \sqrt{234} - 6 \sqrt{2} = \\ 2 \sqrt{2} + 3 \sqrt{3} + 4 \sqrt{2} - 3 \sqrt{26} -6 \sqrt{2} = \\ 6 \sqrt{2} - 6 \sqrt{2} + 3 \sqrt{3} - 3 \sqrt{26} = \\ 3( \sqrt{3} - \sqrt{26} )$