Question

rad18-rad162+rad98=... ​

Answer 1

Răspuns:

$\sqrt{18} - \sqrt{162} + \sqrt{98} \\ 3 \sqrt{2} - 9 \sqrt{2} + 7 \sqrt{2} \\ = \sqrt{2}$

Answer 2

rad 18- rad 162 + rad 98=

= 3 rad 2 - 9rad 2 + rad 98=

= -6 rad 2 + rad 98=

=-6 rad 2 + 7 rad 2=

= rad 2

\sqrt{ 18 } - \sqrt{ 162 } + \sqrt{ 98 }

3\sqrt{2}-\sqrt{162}+\sqrt{98}

3\sqrt{2}-9\sqrt{2}+\sqrt{98}

-6\sqrt{2}+\sqrt{98}

-6\sqrt{2}+7\sqrt{2}

\sqrt{2}

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