Question

rad2^10 : 2^2 + rad4^18 : 2^16 ori (2^2)^3

Answer 1

Răspuns:

$\boxed{\boxed{\mathbf{264}}}$

Explicație pas cu pas:

$\mathbf{\sqrt{2^{10}} : 2^2 + \sqrt{4^{18}} : 2^{16} \cdot (2^2)^3 =}$

$\mathbf{\sqrt{2^{5+5}} : 2^2 + \sqrt{(2^2)^{18}}:2^{16} \cdot 2^{2\cdot 3}= }$

$\mathbf{2^5 : 2^2 +\sqrt{(2^{18})^2}:2^{16} \cdot 2^6 = }$

$\mathbf{ 2^{5-2}+2^{18}:2^{16}\cdot 2^6=}$

$\mathbf{2^3+2^{18-16}\cdot 2^6=}$

$\mathbf{2^3+2^2\cdot 2^6}=$

$\mathbf{2^3+2^{2+6}=}$

$\mathbf{2^3+2^8}=$

$\mathbf{8+256}= \boxed{\mathbf{264}}$

Answer 2

Explicație pas cu pas:

rad2^10 :2^2 + rad4^18 : 2^16 ×(2^2)^3=

2^5 :2^2 +2^18 : 2^16 ×2^6=

2^3 +2^18:2^16×2^6=

2^3+2^2×2^6=

2^3+2^8=8+256=264