Question

radacina patrata a nr 25,81,15 la a 2,3 la 10,(-2) la 2,(-3) la 4,36x4,(-72)x(-2).

Answer 1

$\sqrt{25} =5$

$\sqrt{81} =9$

$\sqrt{15^{2}} =15$

$\sqrt{3^{10}} =(3^{10})^{ \frac{1}{2} }=3^{10*\frac{1}{2}}=3^{5}$

$\sqrt{(-2)^{2}} = \sqrt{4}=2$

$\sqrt{-3^{4,36*4}} =\sqrt{-3^{17,44}}=((-3)^{17,44})^{ \frac{1}{2} }=(-3)^{17,44*\frac{1}{2}}=(-3)^{8,74}$

$\sqrt{(-72)*(-2)} = \sqrt{144}=12$