Question

radical 2 supra 2 minus 3 supra radical 2​

Answer 1

Salut,

$\dfrac{\sqrt2}{2}-\dfrac{3}{\sqrt2}=\dfrac{\sqrt2}{2}-\dfrac{3\sqrt2}{\sqrt2\cdot\sqrt2}=\dfrac{\sqrt2}{2}-\dfrac{3\sqrt2}{2}=\dfrac{\sqrt2-3\sqrt2}{2}=-\dfrac{2\sqrt2}2=-\sqrt2.$

Ai înțeles rezolvarea ?

Green eyes.