Question

radical di 2(radical din 3 +radical din 6)- 2radical din 3(radical din 6-1)+radical din 6(3radical din2+2radicaldin3)=

Answer 1

Sper ca am inteles bine:

[tex] \sqrt{2} *( \sqrt{3} + \sqrt{6} )-2 \sqrt{3}* ( \sqrt{6} -1)+ \sqrt{6} *(3 \sqrt{2} +2 \sqrt{3} )= \sqrt{6}+\sqrt{12}-2\sqrt{18}+2\sqrt{3}+3\sqrt{12}+2\sqrt{18}= \sqrt{6}+2\sqrt{3}+2\sqrt{3}+6\sqrt{3}=\sqrt{6}+10\sqrt{3}[/tex]