Question

[radical din 0,(3)+2radicaldin3 supra3]* radical din 3 +[radical din 0,(2) +4 supra 3 radical  din 2] * radical din 2=

Answer 1

(√(3/9)+2√3/3)x√3+(√(2/9)+4/(3√2))x√2=          Obs:4/3√2=(4x3√2)/3²x√2²
(√3/√9+2√3/3)x√3+(√2/√9+12√2/18)x√2=
(√3/3+2√3/3)x√3+(√2/3+2√2/3)x√2=
(3√3/3)x√3+(3√3/3)x√2=
√3x√3+√3x√2=3+√6

Answer 2

(√0,(3)+2√3/3)*√3+(√0,(2)+4/3√2)*√2=
(√3/3+2√3/3)*√3+(√2/3+4/3√2)*√2=
3√3*√3+(2√2+4√2)/6*√2=
√3*√3+6√2/6*√2=
3+2=
5