Question

radical din 11-4√6... Cine ma ajuta?

Answer 1

rad(11-4rad(6))=rad(11-rad(96))
folosesti formula radicalilor compusi: rad(a+rad(b))=rad((a+c)/2)+rad((a-c)/2)
unde c-rad(a*a-b)
in cazul de fata
a=11
b=96
c=rad(11*11-96)=rad(121-96)=rad(25)=5
rad(11-rad(96))=rad((a+c)/2)+rad((a-c)/2)=rad((11+5)/2)+rad((11-5)/2)=rad(8)+rad(3)=2rad(2)+rad(3)