Question

(radical din 2/2 + radical din 3/2 +...+ radical din 100/2)-(rradical din 1/2+radical din 2/2+....radical din 99/2)

Answer 1

$\sqrt{ \frac{2}{2} }+ \sqrt{ \frac{3}{2} }+...+ \sqrt{ \frac{100}{2} }-( \sqrt{ \frac{1}{2} }+ \sqrt{ \frac{2}{2} }+...+ \sqrt{ \frac{99}{2} }) = \\ \\ =\sqrt{ \frac{2}{2} }+ \sqrt{ \frac{3}{2} }+...+ \sqrt{ \frac{100}{2} }- \sqrt{ \frac{1}{2} }- \sqrt{ \frac{2}{2} }-...- \sqrt{ \frac{99}{2} }= \\ \\ =- \sqrt{ \frac{1}{2} } + \sqrt{ \frac{100}{2} }$