Question

radical din 2 de ordin 4*radical din 8:radical din 8 de ordin4=2

Answer 1

$\sqrt[4]{2} * \sqrt{8} : \sqrt[4]{8} = 2$

$\frac{ \sqrt{8} * \sqrt[4]{2} }{ \sqrt[4]{8} }$
$\frac{ \sqrt[4]{2} * 8^{ \frac{1}{2}} }{8^{ \frac{1}{4}} }$
$\sqrt[4]{2} * 8^{ \frac{1}{2} - \frac{1}{4}}$
$\sqrt[4]{2} * \sqrt[4]{8}$
$2^{ \frac{1}{4}} * 2^ \frac{1}{3} = 2^1 = 2$ - Exact ce trebuia demonstrat