Question

radical din 2 la puterea x = 1+1+2+.....+2 la puterea 999 cum se calculeaza?

Answer 1

x=1+2^0+2^1+...+2^999=1+(2^0+2^1+...+2^999)
2^0+2^1+...+2^999 este o progresie geometrica
b1=1
q=2
S=b1*(q^n -1)/q-1=1*(2^999 -1)(2-1)=2^999 -1

revenim : x=1+(2^0+2^1+...+2^999)=1+2^999 -1=2^999