Question

Radical din 2×(-radical 6)×(-radical12)=

$\sqrt{2 \times ( - \sqrt{6) \times ( - \sqrt{12) = } } }$
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Answer 1

$\sqrt{2 \times ( - \sqrt{6} ) \times ( - \sqrt{12} )} =$

$\sqrt{2 \times ( + \sqrt{6 \times 12} )} =$

$\sqrt{2 \times 6 \sqrt{2} }$

$\sqrt{12 \sqrt{2} } = 2 \sqrt{3 \sqrt{2} }$