Question

radical din 2²+2² × radical din 2⁴+2⁴​

Answer 1

$\sqrt{ {2}^{2} + {2}^{2} } \times \sqrt{ {2}^{4} + {2}^{4} } = \\ \\ = \sqrt{4 + 4} \times \sqrt{16 + 16} = \\ \\ = \sqrt{8} \times \sqrt{32} = \\ \\ = \sqrt{ {2}^{3} } \times \sqrt{ {2}^{5} } = \\ \\ = 2 \sqrt{2} \times 4\sqrt{2} = \\ \\ = 2 \times 4 \times \sqrt{2} \times \sqrt{2} = \\ \\ = 8 \times \sqrt{2} {}^{2} = \\ \\ = 8 \times 2 = 16$