Question

radical din 2x la patrat+1 =1

Answer 1

√2x²+1=1
2x+1=1
2x=0
x=0
cred ca asa e :))

Answer 2

$(\sqrt{2} x)^{2} + 1 = 1$

${ \sqrt{2} }^{2} \times {x}^{2} + 1 = 1$

$2 \times {x}^{2} = 1 - 1 = 0$

${x}^{2} = 0$

$x = 0$