Question

radical din 2x-radical din 72 >xradicaldin 8

Answer 1

$\sqrt{2} x - \sqrt{72} > x \sqrt{8}$

$x \sqrt{2} - x \sqrt{8} > \sqrt{72}$

$x \sqrt{2} - x \times 2 \sqrt{2} > 6 \sqrt{2}$

$x \sqrt{2} - 2x \sqrt{2} > 6 \sqrt{2}$

$- x \sqrt{2} > 6 \sqrt{2} \: | \div ( - \sqrt{2} )$

$x < - 6$

$x \: \in \: ( - \infty , - 6)$