Question

(radical din 3-radical din 2+ radical din 24-3):radical din 12​

Answer 1

Explicație pas cu pas:

$( \sqrt{3} - \sqrt{2} + \sqrt{24} - 3) \div \sqrt{12} = \\ ( \sqrt{3} - \sqrt{2} + 2 \sqrt{6} - 3) \div 2 \sqrt{3} = \\ \frac{ \sqrt{3} - \sqrt{2} + 2 \sqrt{6} - 3 }{2 \sqrt{3} } = \\ \frac{ \sqrt{3} }{2 \sqrt{3} } - \frac{ \sqrt{2} }{ 2 \sqrt{3} } + \frac{2 \sqrt{6} }{2 \sqrt{3} } - \frac{3}{2 \sqrt{3} } = \\ \frac{1}{2} - \frac{ \sqrt{6} }{6} + \sqrt{2} - \frac{3 \sqrt{3} }{6} = \\ \frac{1}{2} - \frac{ \sqrt{6} }{6} + \sqrt{2} - \frac{ \sqrt{3} }{2}$