Question

radical din 5 -1totul la 2 -radical 80=?

Answer 1

[tex](\sqrt{5}-1)^2-\sqrt{80}=\\ =5-2\sqrt{5}+1-4\sqrt{5}=\\ =6-6\sqrt{5}[/tex]

Answer 2

$( \sqrt{5} -1)^2- \sqrt{80}= \sqrt{5^2} -2 \cdot \sqrt{5} \cdot 1+1^2-4 \sqrt{5} = \\ =5-2 \sqrt{5} +1-4 \sqrt{5} =6-6 \sqrt{5}$