Question

Radical din (5-2*radical din 6) = ?

Answer 1

$\sqrt{5-2\sqrt6}=\sqrt{3-2\sqrt2\cdot\sqrt3+2}=\sqrt{(\sqrt3)^2-2\sqrt2\cdot\sqrt3+(\sqrt2)^2}=\\\\=\sqrt{(\sqrt3-\sqrt2)^2}=|\sqrt3-\sqrt2|=\sqrt3-\sqrt2.$

Prin |a| am scris modul de "a".

Green eyes.