Question

-radical din 5-radical din 5!!!Repede va rog

Answer 1

$- \sqrt{5} - \sqrt{5} = - 2 \sqrt{5}$

Answer 2

$-\sqrt 5 - \sqrt 5 = -(\sqrt 5+ \sqrt 5) = -(2\sqrt5) = \\= -2\sqrt5$

$-\sqrt 5 - \sqrt 5 = \sqrt 5\cdot (-1-1) = \sqrt 5 \cdot (-2) = \\ -\sqrt 5 \cdot 2 = -2\sqrt 5$