Question

Radical din 6 : radical din 3 +5 radical din 2

Answer 1

$\frac{ \sqrt{6} }{ \sqrt{3}}+ 5\sqrt{2}= \frac{ \sqrt{18}}{3}+5 \sqrt{2}= \frac{ 3\sqrt{2} }{3} +5 \sqrt{2} = \sqrt{2}+ 5\sqrt{2}=6 \sqrt{2}$