Question

(Radical din 8-3radical din 2 radical 10)(radical din 2 radical din1,6 3radical din 0,4)

Answer 1

(√8-3√2×√10) (√2×√1,6×3√0,4)=
(2√2-3√2×√10)(√2×√16/√10×√4/√10)=
(2√2-3√20)(√2×4/√10×2/√10)=
(2√2-6√5)(4√2/√10×2/√10)=
(2√2-6√5)(8√2/√20)=
(2√2-6√5)(8√2/2√5)=
(2√2×8√2/2√5)-(6√5×8√2/2√5)=
=16/√5-24√2